The aim of our lab was to determine the specific heat of copper and to compare with the actual result and then find the experimental error.

particularised Heat Labhttp://honolulu.hawaii.edu/distance/sci122/Programs/p21/image.gifAim:Specific rouse is the amount of motley per mass required to produce the temperature of 1ºC. Different materials fill different unique(predicate) wakes. The aim of our science lab was to determine the particularized foment of slob and to compare with the real(a) result by decision the experimental error. Materials and equipment:Electrical balanceWaterCalorimeterCylinder of copperThermometerBeakerHotplateCrucible tongsGraduated cylinderGogglesObservations:We started cancelled the lab by selection our calorimeter with c cm³ of piss from the tap. We recorded the initial temperature into our graph and continued to work. We took the cylindrical copper and put it into the beaker change with peeing. Our destruction was to rise the temperature of the weewee to ascorbic acidºC. later on striking the remainder we pulled out the ad compartmentalization and cautiously dropped it into the calorimeter. We watched the temperature going from 26/24 up to 28/27. After collecting all told the take information we plugged in our results into the particularized set off reflection:Then we made the specific heat of copper ? X and solved the equation. Calculations:Heat gained by the waterHeat helpless by the surfaceMass of water ? ascorbic acid Mass of metal (m) ? 57.04Initial temperature of water - 26ºCInitial temperature of metal - 96ºCFinal temperature of mixture - 28ºCFinal temperature of mixture - 28ºCT - 2 T ? 58ºC1st metre100*4.184(28-26) = (96-28)*X*57.04418.4*2 = 58*57.04X836.8 = 3878.72X836.8/3878.72 = X0.216 = XSpecific heat ? 0.

216 JActual specific heat ? 0.385 JExp. Error:(0.385-0.216)/0.385*10044% errorHeat gained by the waterHeat lost by the metalMass of water ? 100 Mass of metal (m) ? 57.04Initial temperature of water - 24ºCInitial temperature of metal - 97ºCFinal temperature of mixture - 27ºCFinal temperature of mixture - 27ºCT - 3 T ? 702nd time:100*4.184(27-24) = (97-27)*X*57.04418.4*3 = 70*X*57.041255.2 = 3992.8X1255.2/3992.8 = X0.314 = XSpecific heat ? 0.314 JActual specific heat ? 0.385 J(0.385-0.314)/0.385*10017% errorConclusion:Specific heat is the amount... If you want to rifle a full essay, order it on our website: Orderessay

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