Blahhh

Chapter 25 Energy from chemical substance answers Q1. Sodium nitrate dissolves right away in urine agree to the equality NaNO3(s) ? NaNO3(aq); ?H = +21.0 kJ breakwater1 aDetermine the postal code change when 1.0 g of solid NaNO3 is turn in water. bWould you expect the temperature to rise or come to pass when sodium nitrate dissolves in water? Explain your answer. A1. an(NaNO3) = =0.0117 jettye 1 bulwarke NaNO3 absorbs 21 kJ vitality 0.0117 groyneee absorbs 0.0117 × 21 kJ = 0.25 kJ bThe temperature will fall. Since the reaction is endoergic the enthaply of reactants is higher than the enthalpy of products, i.e. the reaction absorbs energy. Q2. Calculate the energy released when the by-line quantities of ethane gas blaze mark correspond to the equation: 2ethane(g) + 7O2(g) ? 4CO2(g) + 6H2O(l); ?H = 3120 kJ mol1 a3.00 mol b100 g c10.0 L at SLC A2. aFrom the equation, lend oneself stoichiometry to take care energy released. 2 mol ethane releases 3120 kJ of energy 3.00 mol ethane releases ´ 3.00 kJ So energy = 4680 kJ = 4.68 ´ 103 kJ b tone 1Calculate the pith of ethane, apply n = . n(ethane)= = 3.326 mol spirit 2Use stoichiometry to follow energy released. 2 mol ethane releases 3120 kJ of energy 3.326 mol C2H6 releases 3120 ´ kJ So energy released= 5189 kJ = 5.

19 ´ 103 kJ cStep 1Calculate the amount of ethane, using n = at SLC. n(C2H6)= = 0.4082 mol Step 2Use stoichiometry to encounter energy released. 2 mol C2H6 releases 3120 kJ of energy 0.4082 mol C2H6 releases 3120 ´ kJ So energy released= 636.7 kJ = 637 kJ Q3. What volume of ethane, metrical at STP, must be burn down according to the equation in disbelief 2 in come in to yield 100 kJ of agitate energy? A3. Step 1Use stoichiometry to find the amount of C2H6. 3120 kJ is released by 2 mol 100 kJ is released by 2 ´ mol So n(C2H6)= 2 ´ = 0.641 mol Step 2Calculate the volume of C2H6 at STP, using n = . V(C2H6)= n ´ Vm = 0.641 mol ´ 22.4 L...If you penury to sop up a full essay, order it on our website: Orderessay

If you want to get a full information about our service, visit our page: How it works.