Exercises 31, 32, and 38 (Ch. 10)
31. A new saddle-watching company, Weight Reducers International, advertises that those who join leave lose, on the average, 10 pounds the first two weeks with a type deflexion of 2.8 pounds. A random attempt of 50 good deal who joined the new weight reduction program revealed the suppose loss to be 9 pounds. At the .05 level of signifi ejectce, evoke we intermit that those joining Weight Reducers on average willing lose less than 10 pounds? Determine the p-value.
H0: involve = 10 pounds
H1: mean < 10 pounds
.05/ 2 = .025
critical value is -1.6449
z = (x-mu)/(sigma/sqrt(N))
z = (9-10)/(2.8/sqrt(50))
z = -2.52538
The p value is about 0.006 (from the table)
The z value is lower than the critical value, so reject the null, and conclude that they lose less than 10 pounds.
32. Dole Pineapple, Inc., is concerned that the 16-ounce can of sliced pineapple is being overfilled. Assume the standard deviation of the process is .03 ounces. The qualitycontrol department took a random sample of 50 cans and found that the arithmetic mean weight was 16.05 ounces. At the 5 percent level of significance, can we conclude that the mean weight is greater than 16 ounces? Determine the p-value.
H0: mean < = 16
H1: mean > 16
.05/ 2 = .025
z = (x-mu)/(sigma/sqrt(N))
z = (16.05-16)/(0.03/sqrt(50))
z = 11.
785113
The p value is 0
Since the p value is 0, there it suggests that the cans are over filled.
egest the null hypothesis, the mean is greater than 16
38. A recent oblige in The Wall Street Journal reported that the 30-year mortgage govern is now less than 6 percent. A sample of eight small banks in the Midwest revealed the following 30-year rate (in percent):
4.85.36.54.86.15.86.25.6
At the .01 significance level, can we conclude that the 30-year mortgage rate for small banks is less than 6 percent? Estimate the p-value.
mean = 5.6375
stdev = 0.63457
H0: mean rate = 6
H1: mean rate < 6
t = (x-mu)/(sigma/sqrt(N))
t =...If you want to get a full essay, order it on our website: Orderessay
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